H=2x^2-16x

Solution for H=2x^2-16x equation:

=2H^2-16H

We move all terms to the left:

-(2H^2-16H)=0

We get rid of parentheses

-2H^2+16H=0

a = -2; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·(-2)·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*-2}=\frac{-32}{-4}
=+8
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*-2}=\frac{0}{-4}
=0
$